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A newspaper seller sells (110) newspapers on the first day and (15) more newspapers each next day. On which day will (320) newspapers be sold?

Answer and explanation

Correct answer: 15

This is an arithmetic progression with first term 110 and common difference 15. The sales on the nth day are \(a_n=110+(n-1)\times15\). Putting \(a_n=320\), we get \(110+15(n-1)=320\), so \(15(n-1)=210\), \(n-1=14\), and \(n=15\). Therefore, 320 newspapers will be sold on the 15th day. The nearby option 13 is incorrect because sales on that day would be \(110+12\times15=290\). Exam tip: In day-number AP questions, remember to use \(n-1\).

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermLinear SequenceClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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