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In a festival decoration the first gate has (48) lights and each next gate has (12) more lights. How many lights are there on (9) gates?

Answer and explanation

Correct answer: (864)

The correct answer is C. The gates form an arithmetic progression: first term \\(a=48\\), common difference \\(d=12\\), and number of terms \\(n=9\\). The total is \\(S_n=\frac{n}{2}[2a+(n-1)d]\\). Substituting gives \\(S_9=\frac{9}{2}[2(48)+8(12)] =\frac{9}{2}(96+96)=\frac{9}{2}\times192=864\\). Therefore option C is correct. Option A, 816, is too small and results from an incorrect total or missing increase. Option B, 840, is also not the sum of the nine terms. Option D, 888, is too large and usually comes from adding an extra increase. The terms are 48, 60, 72, 84, 96, 108, 120, 132 and 144; their sum confirms 864. Memory cue: identify first term, difference and number of terms before using the AP sum formula.

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