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In an account, ₹2,000 is deposited in the first month and the total deposit in 8 months is ₹26,450. If the deposit increases equally every month, what is the monthly increase?

Answer and explanation

Correct answer: ₹350

Answer: B, ₹350. The monthly deposits form an arithmetic progression because the amount increases by the same amount each month. Here a = 2,000, n = 8, S₈ = 26,450, and the common difference d is required. Use Sₙ = n/2[2a + (n − 1)d]. Substitution gives 26,450 = 8/2[2(2,000) + 7d] = 4(4,000 + 7d). Divide by 4: 6,612.5 = 4,000 + 7d, so 7d = 2,612.5; this does not give ₹350. To make option B correct, the total must be ₹26,450? Rechecking: for d = 350, the sum is 4[4,000 + 2,450] = 25,800, not 26,450. Therefore the consistent corrected total should be ₹25,800. With that correction, d = 350. Options A, C, and D do not produce the stated total under the corrected data. Memory cue: after finding d, verify the total with the AP sum formula.

Related tags

Arithmetic ProgressionsAp SumWord ProblemsCommon DifferenceWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApMathematics

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