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In an account, 1,500 rupees are deposited in the first month and the total deposit in 7 months is 16,800 rupees. If the deposit increases equally every month, what is the monthly increase?

Answer and explanation

Correct answer: 300 rupees

The governing concept is the sum of the first n terms of an arithmetic progression. The monthly deposits form an AP with first term a = 1,500, number of terms n = 7, total S7 = 16,800, and common difference d equal to the monthly increase. Use S_n = n/2[2a + (n − 1)d]. Substitution gives 16,800 = 7/2[3,000 + 6d]. Multiplying by 2 and dividing by 7 gives 4,800 = 3,000 + 6d, so 6d = 1,800 and d = 300. Hence option B is correct. The other choices result from an incorrect sum or an incorrect division; the required quantity is the common difference, not the final deposit.

Related tags

Arithmetic ProgressionAp Word ProblemCommon DifferenceWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApMathematicsClass 10 Mcq

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