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In an account (1000) rupees are deposited in the first month and the total deposit in (6) months is (9000) rupees. If the deposit increases equally every month then what is the monthly increase?

Answer and explanation

Correct answer: 200

Here, the first term is \(a=1000\), the number of terms is \(n=6\), and the sum is \(S_6=9000\). Using the AP sum formula \(S_n=\frac{n}{2}[2a+(n-1)d]\), we get \(9000=\frac{6}{2}[2(1000)+5d]\). Thus, \(9000=6000+15d\), so \(d=200\). Therefore, the monthly increase is 200 rupees. If the increase were 250 rupees, the total for six months would not be 9000 rupees. Exam tip: in questions stating an equal monthly increase, treat that increase as the common difference \(d\).

Related tags

Arithmetic ProgressionAp Word ProblemsCommon DifferenceSeries SumFinancial ApplicationsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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