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A hotel has (18) rooms on the first floor and (2) more rooms on each next floor. How many rooms are there in (9) floors?

Answer and explanation

Correct answer: 234

The numbers of rooms form an arithmetic progression: 18, 20, 22, \ldots Here, the first term is \(a=18\), the common difference is \(d=2\), and the number of floors is \(n=9\). Thus, \(S_9=\frac{9}{2}[2(18)+(9-1)(2)]=\frac{9}{2}(52)=234\). Therefore, there are 234 rooms in 9 floors. The value 238 is not obtained by adding the rooms on all nine floors. Exam tip: In AP word problems, identify \(a\), \(d\), and \(n\) before applying the formula for \(S_n\).

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of ApClass 10 MathematicsHotel RoomsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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