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A sweet shop sells (28) boxes on the first day and (4) more boxes each next day. How many boxes are sold on the (10)th day?

Answer and explanation

Correct answer: \(64\)

The sales increase by 4 boxes each day, so they form an arithmetic progression. Here, \(a=28\), \(d=4\), and \(n=10\). Thus, \(a_{10}=a+(n-1)d=28+(10-1)\times4=64\). Therefore, 64 boxes are sold on the 10th day. The option \(68\) results from incorrectly adding 10 increases; there are only 9 increases from the first day to the 10th day. Exam tip: use \(n-1\) in the formula for the \(n\)th term of an AP.

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermMathematics Class 10Sequence ApplicationsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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