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In a bank plan (300) rupees are deposited in the first month and (100) rupees more each next month. How much is deposited in the (6)th month?

Answer and explanation

Correct answer: 800 rupees

The monthly deposits form an arithmetic progression (AP) with first term \(a=300\) and common difference \(d=100\). The \(n\)th term is \(a_n=a+(n-1)d\). Therefore, \(a_6=300+(6-1)\times100=800\) rupees, so option B is correct. Choosing 700 rupees counts only four increases, but there are five increases from the first month to the sixth month. Exam tip: always use \((n-1)\) in the formula for the \(n\)th term.

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermFinancial ApplicationsClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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