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Class 10MathematicsArithmetic Progressions (AP)Word problems based on APsEasy
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A worker lays (40) bricks on the first day and (8) more bricks each next day. How many bricks will he lay on the (6)th day?

Answer and explanation

Correct answer: 80

The number of bricks laid each day forms an AP with first term 40 and common difference 8. The sixth term is \(a_6=a+(6-1)d=40+5\times8=80\). Therefore, the worker will lay 80 bricks on the sixth day. Note that 72 is the number of bricks on the fifth day. Exam tip: Use \(a_n=a+(n-1)d\) to avoid counting the first day incorrectly.

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermClass 10 MathematicsSequence ApplicationWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap
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