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Class 10MathematicsArithmetic Progressions (AP)Word problems based on APsEasy
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A worker lays (30) bricks on the first day and (6) more bricks each next day. How many bricks will he lay on the (9)th day?

Answer and explanation

Correct answer: (78)

The number of bricks laid each day forms an AP with first term \(a=30\) and common difference \(d=6\). For the ninth day, \(a_9=a+(9-1)d=30+8\times6=78\). Therefore, the correct answer is (78). (84) would result from adding 6 nine times to 30, but there are only 8 increases after the first day. Exam tip: use \((n-1)d\) in the formula for the \(n\)th term.

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermClass 10 MathematicsSequence ApplicationWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap
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