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In a fair, (100) tickets are sold in the first hour and (50) more tickets each next hour. How many tickets are sold in (6) hours?

Answer and explanation

Correct answer: 1350

The hourly ticket sales form an AP with first term \(a=100\), common difference \(d=50\), and \(n=6\) terms. \(S_6=\frac{6}{2}[2(100)+(6-1)50]=3(450)=1350\). Therefore, 1350 tickets are sold in 6 hours. The value 1300 would fail to include the sixth hour’s sale of 350 tickets. Exam tip: When a word problem asks for a total, use \(S_n\), not just the \(n\)th-term formula.

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of N TermsMathematics Class 10Ticket SalesWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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