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A watch repairer fixes (6) watches in the first hour and (2) more watches each next hour. How many watches are fixed in (8) hours?

Answer and explanation

Correct answer: (104)

The numbers of watches repaired each hour form the AP \(6,8,10,\ldots\), where \(a=6\), \(d=2\), and \(n=8\). Therefore, \(S_8=\frac{8}{2}[2(6)+(8-1)(2)]=4(12+14)=104\). Hence, the correct answer is \(104\). Finding only the work done in the eighth hour would not give the total work. Exam tip: In AP word problems, use \(S_n\) for a total, not \(a_n\).

Related tags

Arithmetic ProgressionAp Word ProblemsSum Of N TermsClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApMathematics

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