समान्तर श्रेणी \(2,5,8,\ldots\) के पहले (10) पदों का योग क्या है?
What is the sum of the first (10) terms of the AP \(2,5,8,\ldots\)?
#ap-sum-easy
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A (145)
B (150)
C (155)
D (160)
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Explanation
Simple Explanation
यहां (a=2), (d=3), (n=10)। \(S_{10}=\frac{10}{2}[2\cdot2+9\cdot3]=155\)। / Here (a=2), (d=3), (n=10). \(S_{10}=\frac{10}{2}[2\cdot2+9\cdot3]=155\).
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समान्तर श्रेणी \(4,8,12,\ldots\) के पहले (15) पदों का योग ज्ञात कीजिए।
Find the sum of the first (15) terms of the AP \(4,8,12,\ldots\).
#ap-sum-first-n
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A (480)
B (460)
C (450)
D (420)
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Simple Explanation
यहां (a=4) और (d=4) है। \(S_{15}=\frac{15}{2}[8+14\cdot4]=480\)। / Here (a=4) and (d=4). \(S_{15}=\frac{15}{2}[8+14\cdot4]=480\).
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यदि (a=6), (d=2), (n=20) है तो \(S_n\) क्या होगा?
If (a=6), (d=2), (n=20), what is \(S_n\)?
#ap-sum-formula
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A (480)
B (500)
C (520)
D (560)
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Explanation
Simple Explanation
(S_n=\frac{n}{2}[2a+(n-1)d]) लगाएं। \(S_{20}=10[12+38]=500\)। / Use (S_n=\frac{n}{2}[2a+(n-1)d]). \(S_{20}=10[12+38]=500\).
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समान्तर श्रेणी \(1,3,5,\ldots\) के पहले (25) पदों का योग क्या है?
What is the sum of the first (25) terms of the AP \(1,3,5,\ldots\)?
#ap-sum-odd-numbers
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A (575)
B (600)
C (625)
D (650)
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Explanation
Simple Explanation
पहले (n) विषम संख्याओं का योग \(n^2\) होता है। इसलिए \(S_{25}=25^2=625\)। / The sum of the first (n) odd numbers is \(n^2\). So \(S_{25}=25^2=625\).
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समान्तर श्रेणी \(10,20,30,\ldots\) के पहले (12) पदों का योग कितना है?
What is the sum of the first (12) terms of the AP \(10,20,30,\ldots\)?
#ap-sum-multiples
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A (760)
B (780)
C (800)
D (820)
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Explanation
Simple Explanation
यहां (a=10), (d=10), (n=12)। \(S_{12}=6[20+110]=780\)। / Here (a=10), (d=10), (n=12). \(S_{12}=6[20+110]=780\).
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समान्तर श्रेणी \(7,14,21,\ldots\) के पहले (10) पदों का योग क्या होगा?
What will be the sum of the first (10) terms of the AP \(7,14,21,\ldots\)?
#ap-sum-multiples-seven
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A (365)
B (375)
C (385)
D (395)
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Explanation
Simple Explanation
यह (7) के गुणजों की श्रेणी है। (S_{10}=\frac{10}{2}(7+70)=385)। / This is the sequence of multiples of (7). (S_{10}=\frac{10}{2}(7+70)=385).
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यदि किसी AP का पहला पद (5), अंतिम पद (45) और पदों की संख्या (9) है तो योग क्या है?
If the first term of an AP is (5), the last term is (45), and the number of terms is (9), what is the sum?
#ap-sum-first-last
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A (215)
B (225)
C (235)
D (245)
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Explanation
Simple Explanation
जब पहला और अंतिम पद दिए हों तो (S_n=\frac{n}{2}(a+l))। (S_9=\frac{9}{2}(5+45)=225)। / When first and last terms are given use (S_n=\frac{n}{2}(a+l)). (S_9=\frac{9}{2}(5+45)=225).
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समान्तर श्रेणी \(3,6,9,\ldots\) के पहले (30) पदों का योग ज्ञात कीजिए।
Find the sum of the first (30) terms of the AP \(3,6,9,\ldots\).
#ap-sum-simple
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A (1395)
B (1405)
C (1415)
D (1425)
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Explanation
Simple Explanation
यहां अंतिम पद (90) है। (S_{30}=\frac{30}{2}(3+90)=1395)। / Here the last term is (90). (S_{30}=\frac{30}{2}(3+90)=1395).
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समान्तर श्रेणी \(20,18,16,\ldots\) के पहले (8) पदों का योग क्या है?
What is the sum of the first (8) terms of the AP \(20,18,16,\ldots\)?
#ap-sum-decreasing
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A (100)
B (104)
C (108)
D (112)
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Explanation
Simple Explanation
यह घटती AP है जिसमें (d=-2) है। (S_8=\frac{8}{2}[40+7(-2)]=104)। / This is a decreasing AP with (d=-2). (S_8=\frac{8}{2}[40+7(-2)]=104).
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यदि AP \(9,13,17,\ldots\) है तो पहले (11) पदों का योग क्या है?
If the AP is \(9,13,17,\ldots\), what is the sum of the first (11) terms?
#ap-sum-eleven-terms
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A (319)
B (329)
C (339)
D (349)
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यहां (a=9), (d=4), (n=11)। \(S_{11}=\frac{11}{2}[18+40]=319\)। / Here (a=9), (d=4), (n=11). \(S_{11}=\frac{11}{2}[18+40]=319\).
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समान्तर श्रेणी \(12,17,22,\ldots\) के पहले (14) पदों का योग कितना है?
What is the sum of the first (14) terms of the AP \(12,17,22,\ldots\)?
#ap-sum-last-term
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A (605)
B (615)
C (623)
D (629)
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Explanation
Simple Explanation
अंतिम पद \(12+13\cdot5=77\) है। (S_{14}=\frac{14}{2}(12+77)=623)। / The last term is \(12+13\cdot5=77\). (S_{14}=\frac{14}{2}(12+77)=623).
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समान्तर श्रेणी \(5,10,15,\ldots\) के पहले (18) पदों का योग क्या होगा?
What will be the sum of the first (18) terms of the AP \(5,10,15,\ldots\)?
#ap-sum-five-multiples
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A (845)
B (855)
C (865)
D (875)
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Explanation
Simple Explanation
यहां अंतिम पद (90) है। (S_{18}=\frac{18}{2}(5+90)=855)। / Here the last term is (90). (S_{18}=\frac{18}{2}(5+90)=855).
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यदि (a=8), (d=3), (n=16) है तो \(S_{16}\) कितना होगा?
If (a=8), (d=3), (n=16), what is \(S_{16}\)?
#ap-sum-given-values
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A (488)
B (494)
C (502)
D (508)
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Explanation
Simple Explanation
\(S_{16}=\frac{16}{2}[16+15\cdot3]\)। इसलिए \(S_{16}=8\cdot61=488\)। / \(S_{16}=\frac{16}{2}[16+15\cdot3]\). Therefore \(S_{16}=8\cdot61=488\).
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समान्तर श्रेणी \(6,11,16,\ldots\) के पहले (9) पदों का योग क्या है?
What is the sum of the first (9) terms of the AP \(6,11,16,\ldots\)?
#ap-sum-nine-terms
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A (230)
B (234)
C (238)
D (242)
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Explanation
Simple Explanation
\(a_9=6+8\cdot5=46\) है। (S_9=\frac{9}{2}(6+46)=234)। / \(a_9=6+8\cdot5=46\). (S_9=\frac{9}{2}(6+46)=234).
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पहले (20) प्राकृतिक संख्याओं का योग क्या है?
What is the sum of the first (20) natural numbers?
#ap-sum-natural-numbers
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A (190)
B (200)
C (210)
D (220)
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Explanation
Simple Explanation
प्राकृतिक संख्याओं के लिए (S_n=\frac{n(n+1)}{2})। \(S_{20}=\frac{20\cdot21}{2}=210\)। / For natural numbers (S_n=\frac{n(n+1)}{2}). \(S_{20}=\frac{20\cdot21}{2}=210\).
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पहले (16) सम प्राकृतिक संख्याओं का योग कितना है?
What is the sum of the first (16) even natural numbers?
#ap-sum-even-numbers
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A (272)
B (270)
C (268)
D (264)
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Explanation
Simple Explanation
पहली (n) सम संख्याओं का योग (n(n+1)) होता है। \(16\cdot17=272\)। / The sum of the first (n) even numbers is (n(n+1)). \(16\cdot17=272\).
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समान्तर श्रेणी \(15,25,35,\ldots\) के पहले (13) पदों का योग क्या है?
What is the sum of the first (13) terms of the AP \(15,25,35,\ldots\)?
#ap-sum-thirteen-terms
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A (955)
B (965)
C (975)
D (985)
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Explanation
Simple Explanation
अंतिम पद \(15+12\cdot10=135\) है। (S_{13}=\frac{13}{2}(15+135)=975)। / The last term is \(15+12\cdot10=135\). (S_{13}=\frac{13}{2}(15+135)=975).
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यदि पहले (n) पदों का योग (S_n=\frac{n}{2}(3n+1)) है तो \(S_{10}\) क्या होगा?
If the sum of the first (n) terms is (S_n=\frac{n}{2}(3n+1)), what is \(S_{10}\)?
#ap-sum-direct-formula
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A (145)
B (155)
C (165)
D (175)
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Explanation
Simple Explanation
सूत्र में (n=10) रखें। (S_{10}=\frac{10}{2}(31)=155)। / Put (n=10) in the formula. (S_{10}=\frac{10}{2}(31)=155).
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समान्तर श्रेणी \(30,27,24,\ldots\) के पहले (10) पदों का योग ज्ञात कीजिए।
Find the sum of the first (10) terms of the AP \(30,27,24,\ldots\).
#ap-sum-negative-difference
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A (155)
B (160)
C (165)
D (170)
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Explanation
Simple Explanation
यहां (d=-3) है। (S_{10}=5[60+9(-3)]=165)। / Here (d=-3). (S_{10}=5[60+9(-3)]=165).
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एक AP का (a=2), (l=38) और (n=10) है। \(S_n\) क्या होगा?
An AP has (a=2), (l=38), and (n=10). What is \(S_n\)?
#ap-sum-first-last-easy
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A (180)
B (190)
C (200)
D (210)
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Explanation
Simple Explanation
पहला और अंतिम पद दिए हैं। (S_{10}=\frac{10}{2}(2+38)=200)। / The first and last terms are given. (S_{10}=\frac{10}{2}(2+38)=200).
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समान्तर श्रेणी \(11,22,33,\ldots\) के पहले (9) पदों का योग कितना है?
What is the sum of the first (9) terms of the AP \(11,22,33,\ldots\)?
#ap-sum-eleven-multiples
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A (485)
B (495)
C (505)
D (515)
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Simple Explanation
अंतिम पद (99) है। (S_9=\frac{9}{2}(11+99)=495)। / The last term is (99). (S_9=\frac{9}{2}(11+99)=495).
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समान्तर श्रेणी \(13,16,19,\ldots\) के पहले (12) पदों का योग क्या है?
What is the sum of the first (12) terms of the AP \(13,16,19,\ldots\)?
#ap-sum-twelve-terms
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A (354)
B (356)
C (358)
D (360)
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Explanation
Simple Explanation
अंतिम पद \(13+11\cdot3=46\) है। (S_{12}=\frac{12}{2}(13+46)=354)। / The last term is \(13+11\cdot3=46\). (S_{12}=\frac{12}{2}(13+46)=354).
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यदि (a=25), (d=-2), (n=15) है तो \(S_{15}\) क्या होगा?
If (a=25), (d=-2), (n=15), what is \(S_{15}\)?
#ap-sum-decreasing-values
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A (155)
B (160)
C (165)
D (170)
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Explanation
Simple Explanation
घटती AP में (d=-2) रखें। (S_{15}=\frac{15}{2}[50+14(-2)]=165)। / In a decreasing AP use (d=-2). (S_{15}=\frac{15}{2}[50+14(-2)]=165).
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समान्तर श्रेणी \(18,21,24,\ldots\) के पहले (20) पदों का योग कितना होगा?
What will be the sum of the first (20) terms of the AP \(18,21,24,\ldots\)?
#ap-sum-twenty-terms
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A (910)
B (920)
C (930)
D (940)
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Explanation
Simple Explanation
अंतिम पद \(18+19\cdot3=75\) है। (S_{20}=\frac{20}{2}(18+75)=930)। / The last term is \(18+19\cdot3=75\). (S_{20}=\frac{20}{2}(18+75)=930).
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समान्तर श्रेणी \(40,35,30,\ldots\) के पहले (7) पदों का योग क्या है?
What is the sum of the first (7) terms of the AP \(40,35,30,\ldots\)?
#ap-sum-seven-terms
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A (165)
B (170)
C (175)
D (180)
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Explanation
Simple Explanation
अंतिम पद (40+6(-5)=10) है। (S_7=\frac{7}{2}(40+10)=175)। / The last term is (40+6(-5)=10). (S_7=\frac{7}{2}(40+10)=175).
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एक AP में (n=8), (a=4) और (l=32) है। योग क्या है?
In an AP (n=8), (a=4), and (l=32). What is the sum?
#ap-sum-last-given
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A (134)
B (140)
C (144)
D (150)
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Explanation
Simple Explanation
(S_n=\frac{n}{2}(a+l)) लगाएं। (S_8=\frac{8}{2}(4+32)=144)। / Use (S_n=\frac{n}{2}(a+l)). (S_8=\frac{8}{2}(4+32)=144).
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समान्तर श्रेणी \(2,4,6,\ldots\) के पहले (50) पदों का योग क्या है?
What is the sum of the first (50) terms of the AP \(2,4,6,\ldots\)?
#ap-sum-even-first-fifty
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A (2500)
B (2550)
C (2600)
D (2650)
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Explanation
Simple Explanation
पहले (n) सम पदों का योग (n(n+1)) है। \(50\cdot51=2550\)। / The sum of the first (n) even terms is (n(n+1)). \(50\cdot51=2550\).
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समान्तर श्रेणी \(9,18,27,\ldots\) के पहले (12) पदों का योग कितना है?
What is the sum of the first (12) terms of the AP \(9,18,27,\ldots\)?
#ap-sum-nine-multiples
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A (692)
B (702)
C (712)
D (722)
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Explanation
Simple Explanation
अंतिम पद (108) है। (S_{12}=\frac{12}{2}(9+108)=702)। / The last term is (108). (S_{12}=\frac{12}{2}(9+108)=702).
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समान्तर श्रेणी \(100,90,80,\ldots\) के पहले (6) पदों का योग क्या है?
What is the sum of the first (6) terms of the AP \(100,90,80,\ldots\)?
#ap-sum-decreasing-six
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A (430)
B (440)
C (450)
D (460)
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Explanation
Simple Explanation
छठा पद (50) है। (S_6=\frac{6}{2}(100+50)=450)। / The sixth term is (50). (S_6=\frac{6}{2}(100+50)=450).
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यदि (S_n=\frac{n}{2}(2n+4)) है तो \(S_{12}\) क्या होगा?
If (S_n=\frac{n}{2}(2n+4)), what is \(S_{12}\)?
#ap-sum-substitution
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A (156)
B (160)
C (168)
D (172)
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Explanation
Simple Explanation
सूत्र में (n=12) रखें। (S_{12}=\frac{12}{2}(24+4)=168)। / Put (n=12) in the formula. (S_{12}=\frac{12}{2}(24+4)=168).
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समान्तर श्रेणी \(16,24,32,\ldots\) के पहले (10) पदों का योग क्या होगा?
What will be the sum of the first (10) terms of the AP \(16,24,32,\ldots\)?
#ap-sum-ten-terms
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A (500)
B (510)
C (520)
D (530)
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Explanation
Simple Explanation
दसवां पद (88) है। (S_{10}=\frac{10}{2}(16+88)=520)। / The tenth term is (88). (S_{10}=\frac{10}{2}(16+88)=520).
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एक AP के पहले (5) पद (3,7,11,15,19) हैं। इनका योग क्या है?
The first (5) terms of an AP are (3,7,11,15,19). What is their sum?
#ap-sum-direct-addition
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A (55)
B (57)
C (59)
D (61)
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Explanation
Simple Explanation
सीधे जोड़ने पर (3+7+11+15+19=55)। छोटे (n) में सीधा जोड़ भी उपयोगी है। / Adding directly (3+7+11+15+19=55). For small (n), direct addition is useful too.
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समान्तर श्रेणी \(21,28,35,\ldots\) के पहले (8) पदों का योग कितना है?
What is the sum of the first (8) terms of the AP \(21,28,35,\ldots\)?
#ap-sum-eight-terms
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A (360)
B (364)
C (368)
D (372)
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Explanation
Simple Explanation
आठवां पद (70) है। (S_8=\frac{8}{2}(21+70)=364)। / The eighth term is (70). (S_8=\frac{8}{2}(21+70)=364).
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यदि (a=1), (d=1), (n=100) है तो \(S_{100}\) क्या होगा?
If (a=1), (d=1), (n=100), what is \(S_{100}\)?
#ap-sum-hundred-natural
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A (5000)
B (5050)
C (5100)
D (5150)
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Explanation
Simple Explanation
यह पहले (100) प्राकृतिक संख्याओं का योग है। \(S_{100}=\frac{100\cdot101}{2}=5050\)। / This is the sum of the first (100) natural numbers. \(S_{100}=\frac{100\cdot101}{2}=5050\).
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समान्तर श्रेणी \(50,45,40,\ldots\) के पहले (9) पदों का योग क्या है?
What is the sum of the first (9) terms of the AP \(50,45,40,\ldots\)?
#ap-sum-decreasing-nine
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A (260)
B (270)
C (280)
D (290)
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नौवां पद (10) है। (S_9=\frac{9}{2}(50+10)=270)। / The ninth term is (10). (S_9=\frac{9}{2}(50+10)=270).
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समान्तर श्रेणी \(0,4,8,\ldots\) के पहले (11) पदों का योग ज्ञात कीजिए।
Find the sum of the first (11) terms of the AP \(0,4,8,\ldots\).
#ap-sum-zero-first-term
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A (210)
B (220)
C (230)
D (240)
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Simple Explanation
अंतिम पद (40) है। (S_{11}=\frac{11}{2}(0+40)=220)। / The last term is (40). (S_{11}=\frac{11}{2}(0+40)=220).
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यदि (a=3), (d=6), (n=12) है तो पहले (12) पदों का योग क्या है?
If (a=3), (d=6), (n=12), what is the sum of the first (12) terms?
#ap-sum-given-a-d
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A (432)
B (438)
C (444)
D (450)
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Explanation
Simple Explanation
\(S_{12}=\frac{12}{2}[6+11\cdot6]\)। इसलिए \(S_{12}=6\cdot72=432\)। / \(S_{12}=\frac{12}{2}[6+11\cdot6]\). Therefore \(S_{12}=6\cdot72=432\).
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समान्तर श्रेणी \(14,18,22,\ldots\) के पहले (25) पदों का योग कितना है?
What is the sum of the first (25) terms of the AP \(14,18,22,\ldots\)?
#ap-sum-twenty-five
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A (1535)
B (1550)
C (1565)
D (1575)
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अंतिम पद \(14+24\cdot4=110\) है। (S_{25}=\frac{25}{2}(14+110)=1550)। / The last term is \(14+24\cdot4=110\). (S_{25}=\frac{25}{2}(14+110)=1550).
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एक AP में पहला पद (12), अंतिम पद (72) और कुल पद (11) हैं। योग क्या होगा?
In an AP, the first term is (12), the last term is (72), and total terms are (11). What is the sum?
#ap-sum-given-last
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A (442)
B (452)
C (462)
D (472)
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(S_n=\frac{n}{2}(a+l)) से (S_{11}=\frac{11}{2}(12+72)=462)। / Using (S_n=\frac{n}{2}(a+l)), (S_{11}=\frac{11}{2}(12+72)=462).
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समान्तर श्रेणी \(24,30,36,\ldots\) के पहले (16) पदों का योग क्या है?
What is the sum of the first (16) terms of the AP \(24,30,36,\ldots\)?
#ap-sum-sixteen
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A (1084)
B (1094)
C (1104)
D (1114)
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सोलहवां पद (114) है। (S_{16}=\frac{16}{2}(24+114)=1104)। / The sixteenth term is (114). (S_{16}=\frac{16}{2}(24+114)=1104).
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पहले (15) विषम प्राकृतिक संख्याओं का योग क्या है?
What is the sum of the first (15) odd natural numbers?
#ap-sum-odd-fifteen
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A (215)
B (225)
C (235)
D (245)
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Explanation
Simple Explanation
पहले (n) विषम संख्याओं का योग \(n^2\) है। \(15^2=225\)। / The sum of the first (n) odd numbers is \(n^2\). \(15^2=225\).
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समान्तर श्रेणी \(17,22,27,\ldots\) के पहले (10) पदों का योग कितना है?
What is the sum of the first (10) terms of the AP \(17,22,27,\ldots\)?
#ap-sum-ten-easy
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A (385)
B (390)
C (395)
D (400)
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दसवां पद (62) है। (S_{10}=\frac{10}{2}(17+62)=395)। / The tenth term is (62). (S_{10}=\frac{10}{2}(17+62)=395).
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यदि \(S_n=2n^2+n\) है तो \(S_9\) क्या होगा?
If \(S_n=2n^2+n\), what is \(S_9\)?
#ap-sum-polynomial
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A (171)
B (173)
C (175)
D (177)
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Explanation
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सूत्र में (n=9) रखें। \(S_9=2\cdot9^2+9=171\)। / Put (n=9) in the formula. \(S_9=2\cdot9^2+9=171\).
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समान्तर श्रेणी \(60,54,48,\ldots\) के पहले (5) पदों का योग क्या होगा?
What will be the sum of the first (5) terms of the AP \(60,54,48,\ldots\)?
#ap-sum-five-decreasing
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A (230)
B (240)
C (250)
D (260)
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Explanation
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पांचवां पद (36) है। (S_5=\frac{5}{2}(60+36)=240)। / The fifth term is (36). (S_5=\frac{5}{2}(60+36)=240).
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समान्तर श्रेणी \(8,16,24,\ldots\) के पहले (14) पदों का योग कितना है?
What is the sum of the first (14) terms of the AP \(8,16,24,\ldots\)?
#ap-sum-fourteen
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A (820)
B (830)
C (840)
D (850)
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चौदहवां पद (112) है। (S_{14}=\frac{14}{2}(8+112)=840)। / The fourteenth term is (112). (S_{14}=\frac{14}{2}(8+112)=840).
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एक AP में (a=11), (d=11), (n=20) है। योग क्या है?
In an AP (a=11), (d=11), (n=20). What is the sum?
#ap-sum-multiples-eleven
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A (2310)
B (2320)
C (2330)
D (2340)
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Simple Explanation
यह (11) के पहले (20) गुणजों का योग है। (S_{20}=\frac{20}{2}(11+220)=2310)। / This is the sum of the first (20) multiples of (11). (S_{20}=\frac{20}{2}(11+220)=2310).
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समान्तर श्रेणी \(5,9,13,\ldots\) के पहले (18) पदों का योग क्या होगा?
What will be the sum of the first (18) terms of the AP \(5,9,13,\ldots\)?
#ap-sum-eighteen
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A (680)
B (690)
C (700)
D (702)
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अठारहवां पद \(5+17\cdot4=73\) है। (S_{18}=\frac{18}{2}(5+73)=702)। / The eighteenth term is \(5+17\cdot4=73\). (S_{18}=\frac{18}{2}(5+73)=702).
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यदि (a=7), (d=0), (n=12) है तो \(S_{12}\) क्या होगा?
If (a=7), (d=0), (n=12), what is \(S_{12}\)?
#ap-sum-zero-difference
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A (84)
B (88)
C (92)
D (96)
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Explanation
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सभी (12) पद (7) हैं। इसलिए \(S_{12}=12\times7=84\)। / All (12) terms are (7). Therefore \(S_{12}=12\times7=84\).
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समान्तर श्रेणी \(19,29,39,\ldots\) के पहले (6) पदों का योग क्या है?
What is the sum of the first (6) terms of the AP \(19,29,39,\ldots\)?
#ap-sum-six-terms
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A (264)
B (266)
C (268)
D (270)
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छठा पद (69) है। (S_6=\frac{6}{2}(19+69)=264)। / The sixth term is (69). (S_6=\frac{6}{2}(19+69)=264).
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समान्तर श्रेणी \(32,36,40,\ldots\) के पहले (22) पदों का योग कितना है?
What is the sum of the first (22) terms of the AP \(32,36,40,\ldots\)?
#ap-sum-twenty-two
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A (1600)
B (1616)
C (1628)
D (1636)
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Explanation
Simple Explanation
बाईसवां पद \(32+21\cdot4=116\) है। (S_{22}=\frac{22}{2}(32+116)=1628)। / The twenty-second term is \(32+21\cdot4=116\). (S_{22}=\frac{22}{2}(32+116)=1628).
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