Concept-wise Practice

zero comparison MCQ Questions for Class 11

zero comparison se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with zero comparison.

असमानता \(21-7x\le 0\) का हल क्या है?

What is the solution of the inequality \(21-7x\le 0\)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge 3\)

Step 1

Concept

From \(21-7x\le 0\), we get \(-7x\le -21\), so \(x\ge 3\). The direction changes when dividing by a negative number.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge 3\). From \(21-7x\le 0\), we get \(-7x\le -21\), so \(x\ge 3\). The direction changes when dividing by a negative number.

Step 3

Exam Tip

\(21-7x\le 0\) से \(-7x\le -21\), इसलिए \(x\ge 3\)। ऋणात्मक से भाग देने पर दिशा बदलती है।

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असमानता \(6-2x\ge 0\) का हल क्या है?

What is the solution of the inequality \(6-2x\ge 0\)?

Explanation opens after your attempt
Correct Answer

A. \(x\le 3\)

Step 1

Concept

We get \(-2x\ge -6\), so division by (-2) gives \(x\le 3\). Reverse the sign while dividing by a negative number.

Step 2

Why this answer is correct

The correct answer is A. \(x\le 3\). We get \(-2x\ge -6\), so division by (-2) gives \(x\le 3\). Reverse the sign while dividing by a negative number.

Step 3

Exam Tip

\(-2x\ge -6\), इसलिए (-2) से भाग देने पर \(x\le 3\)। ऋणात्मक से भाग देते समय चिह्न पलटें।

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असमानता (9-3x>0) का हल क्या है?

What is the solution of the inequality (9-3x>0)?

Explanation opens after your attempt
Correct Answer

A. (x<3)

Step 1

Concept

From (9-3x>0), we get (-3x>-9), so division by (-3) gives (x<3). Reversing the sign is necessary in negative division.

Step 2

Why this answer is correct

The correct answer is A. (x<3). From (9-3x>0), we get (-3x>-9), so division by (-3) gives (x<3). Reversing the sign is necessary in negative division.

Step 3

Exam Tip

(9-3x>0) से (-3x>-9), इसलिए (-3) से भाग देने पर (x<3)। ऋणात्मक भाग में चिह्न पलटना जरूरी है।

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