यदि (p(x)=x-2+ax+7) का एक शून्यक \(\sqrt{7}\) है और (a) परिमेय है, तो (a) क्या होगा?
If one zero of (p(x)=x-2+ax+7) is \(\sqrt{7}\) and (a) is rational, what is (a)?
Explanation opens after your attempt
Correct Answer
A. (0)
Concept
The other zero will be \(-\sqrt{7}\), so the sum is (0) and (a=-0=0). With rational coefficients, take the conjugate zero.
Why this answer is correct
The correct answer is A. (0). The other zero will be \(-\sqrt{7}\), so the sum is (0) and (a=-0=0). With rational coefficients, take the conjugate zero.
Exam Tip
दूसरा शून्यक \(-\sqrt{7}\) होगा, इसलिए योग (0) और (a=-0=0) है। परिमेय गुणांक में संयुग्मी शून्यक लेना जरूरी है।
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