संख्या 48510 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 48510?
Explanation opens after your attempt
Correct Answer
A. \(2\times3^2\times5\times7^2\times11\)
Concept
Write \(48510=90\times539\).
Why this answer is correct
\(90=2\times3^2\times5\) and \(539=7^2\times11\), so \(48510=2\times3^2\times5\times7^2\times11\).
Exam Tip
Give prime form to both 90 and 539. चरण 1: \(48510=90\times539\) लिखें। चरण 2: \(90=2\times3^2\times5\) और \(539=7^2\times11\), इसलिए \(48510=2\times3^2\times5\times7^2\times11\)। चरण 3: 90 और 539 दोनों को अभाज्य रूप दें।
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