Concept-wise Practice

fourth-power MCQ Questions for Class 10

fourth-power se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with fourth-power.

Question 1/3 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि \(x^2-5x+1=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^4+\beta^4\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-5x+1=0\), what is \(\alpha^4+\beta^4\)?

Explanation opens after your attempt
Correct Answer

A. (527)

Step 1

Concept

Here \(\alpha+\beta=5\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=23\), then \(\alpha^4+\beta^4=23^2-2=527\).

Step 2

Why this answer is correct

The correct answer is A. (527). Here \(\alpha+\beta=5\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=23\), then \(\alpha^4+\beta^4=23^2-2=527\).

Step 3

Exam Tip

\(\alpha+\beta=5\) और \(\alpha\beta=1\) है। पहले \(\alpha^2+\beta^2=23\), फिर \(\alpha^4+\beta^4=23^2-2=527\)।

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Question 2/3 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(x^2-3x+1=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^4+\beta^4\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-3x+1=0\), what is \(\alpha^4+\beta^4\)?

Explanation opens after your attempt
Correct Answer

C. (47)

Step 1

Concept

Here \(\alpha+\beta=3\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=7\), then \(\alpha^4+\beta^4=7^2-2=47\).

Step 2

Why this answer is correct

The correct answer is C. (47). Here \(\alpha+\beta=3\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=7\), then \(\alpha^4+\beta^4=7^2-2=47\).

Step 3

Exam Tip

\(\alpha+\beta=3\) और \(\alpha\beta=1\) है। पहले \(\alpha^2+\beta^2=7\), फिर \(\alpha^4+\beta^4=7^2-2=47\)।

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Question 3/3 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2-4x+1=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\alpha^4+\beta^4\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-4x+1=0\), what is \(\alpha^4+\beta^4\)?

Explanation opens after your attempt
Correct Answer

A. (194)

Step 1

Concept

Here \(\alpha+\beta=4\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=14\), then \(\alpha^4+\beta^4=14^2-2=194\).

Step 2

Why this answer is correct

The correct answer is A. (194). Here \(\alpha+\beta=4\) and \(\alpha\beta=1\). First \(\alpha^2+\beta^2=14\), then \(\alpha^4+\beta^4=14^2-2=194\).

Step 3

Exam Tip

\(\alpha+\beta=4\) और \(\alpha\beta=1\) है। पहले \(\alpha^2+\beta^2=14\), फिर \(\alpha^4+\beta^4=14^2-2=194\)।

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