Concept-wise Practice

exponent-cancellation MCQ Questions for Class 10

exponent-cancellation se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with exponent-cancellation.

\(\frac{2^5\cdot 5^2}{2^{10}\cdot 5^6}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{2^5\cdot 5^2}{2^{10}\cdot 5^6}\) terminate?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

After cancellation, the denominator becomes \(2^5\cdot 5^4\). The larger exponent is (5), so the decimal terminates after (5) places.

Step 2

Why this answer is correct

The correct answer is B. (5). After cancellation, the denominator becomes \(2^5\cdot 5^4\). The larger exponent is (5), so the decimal terminates after (5) places.

Step 3

Exam Tip

कटौती के बाद हर \(2^5\cdot 5^4\) बचेगा। बड़ी घात (5) है इसलिए दशमलव (5) स्थानों पर समाप्त होगा।

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\(\frac{2^4\cdot 5^3}{2^9\cdot 5^5}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{2^4\cdot 5^3}{2^9\cdot 5^5}\) terminate?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

After cancellation, the denominator becomes \(2^5\cdot 5^2\). The larger exponent is (5), so the decimal terminates after (5) places.

Step 2

Why this answer is correct

The correct answer is B. (5). After cancellation, the denominator becomes \(2^5\cdot 5^2\). The larger exponent is (5), so the decimal terminates after (5) places.

Step 3

Exam Tip

कटौती के बाद हर \(2^5\cdot 5^2\) बचेगा। बड़ी घात (5) है इसलिए दशमलव (5) स्थानों पर समाप्त होगा।

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\(\frac{2^3\cdot 5^2}{2^7\cdot 5^5}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many decimal places will \(\frac{2^3\cdot 5^2}{2^7\cdot 5^5}\) terminate?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

After cancellation, the denominator becomes \(2^4\cdot 5^3\). The larger exponent is (4), so the decimal terminates after (4) places.

Step 2

Why this answer is correct

The correct answer is B. (4). After cancellation, the denominator becomes \(2^4\cdot 5^3\). The larger exponent is (4), so the decimal terminates after (4) places.

Step 3

Exam Tip

कटौती के बाद हर \(2^4\cdot 5^3\) बचेगा। बड़ी घात (4) है, इसलिए दशमलव (4) स्थानों पर समाप्त होगा।

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\(\frac{5^k}{2^3\cdot 5^8}\) का दशमलव ठीक (3) स्थानों पर समाप्त हो, इसके लिए (k) का न्यूनतम मान क्या होगा?

What is the least value of (k) for \(\frac{5^k}{2^3\cdot 5^8}\) to terminate exactly after (3) decimal places?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

\(5^k\) cancels with \(5^8\) in the denominator.

Step 2

Why this answer is correct

The denominator becomes \(2^3\cdot 5^{8-k}\). For exactly (3) places, \(8-k\leq 3\), so the least (k) is (5).

Step 3

Exam Tip

For a least value, solve the inequality carefully. चरण 1: \(5^k\) हर के \(5^8\) से कटेगा। चरण 2: हर \(2^3\cdot 5^{8-k}\) बनेगा। ठीक (3) स्थानों के लिए \(8-k\leq 3\) चाहिए, इसलिए न्यूनतम (k=5)। चरण 3: न्यूनतम मान में असमानता को सही दिशा में हल करें।

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