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expert-mcq MCQ Questions for Class 10

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Practice Questions

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यदि (n) सबसे छोटा धनात्मक पूर्णांक है जिससे \(\frac{n}{2^2\cdot 3^4\cdot 5\cdot 13}\) का दशमलव सांत हो, तो (n) क्या होगा?

If (n) is the smallest positive integer for which \(\frac{n}{2^2\cdot 3^4\cdot 5\cdot 13}\) has a terminating decimal, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (1053)

Step 1

Concept

For a terminating decimal, \(3^4\) and (13) must cancel completely, so \(n=3^4\cdot 13=1053\). For the least value, cancel only the unwanted prime factors.

Step 2

Why this answer is correct

The correct answer is C. (1053). For a terminating decimal, \(3^4\) and (13) must cancel completely, so \(n=3^4\cdot 13=1053\). For the least value, cancel only the unwanted prime factors.

Step 3

Exam Tip

सांत दशमलव के लिए \(3^4\) और (13) पूरी तरह कटने चाहिए, इसलिए \(n=3^4\cdot 13=1053\)। न्यूनतम मान में केवल अनचाहे अभाज्य गुणनखंड काटें।

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