Concept-wise Practice

endpoint-values MCQ Questions for Class 12

endpoint-values se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with endpoint-values.

\(\cos^{-1}0-\sin^{-1}0\) का मान क्या है?

What is the value of \(\cos^{-1}0-\sin^{-1}0\)?

Explanation opens after your attempt
Correct Answer

B. \(\frac{\pi}{2}\)

Step 1

Concept

Since \(\cos^{-1}0=\frac{\pi}{2}\) and \(\sin^{-1}0=0\), the difference is \(\frac{\pi}{2}\). Inverse trigonometric values at zero are very useful.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{\pi}{2}\). Since \(\cos^{-1}0=\frac{\pi}{2}\) and \(\sin^{-1}0=0\), the difference is \(\frac{\pi}{2}\). Inverse trigonometric values at zero are very useful.

Step 3

Exam Tip

\(\cos^{-1}0=\frac{\pi}{2}\) और \(\sin^{-1}0=0\), इसलिए अंतर \(\frac{\pi}{2}\) है। शून्य के उल्टे त्रिकोणमितीय मान बहुत उपयोगी हैं।

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\(\sin^{-1}1+\cos^{-1}1\) का मान क्या है?

What is the value of \(\sin^{-1}1+\cos^{-1}1\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{\pi}{2}\)

Step 1

Concept

Here \(\sin^{-1}1=\frac{\pi}{2}\) and \(\cos^{-1}1=0\), so the sum is \(\frac{\pi}{2}\). Remember endpoint values.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{\pi}{2}\). Here \(\sin^{-1}1=\frac{\pi}{2}\) and \(\cos^{-1}1=0\), so the sum is \(\frac{\pi}{2}\). Remember endpoint values.

Step 3

Exam Tip

\(\sin^{-1}1=\frac{\pi}{2}\) और \(\cos^{-1}1=0\), इसलिए योग \(\frac{\pi}{2}\) है। अंत बिंदुओं के मान याद रखें।

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