यदि (n(A)=102), (n(B)=95), (n\(A\cup B\)=143) और (n(U)=190) है, तो (n\(A^c\cap B^c\)) कितना होगा?
If (n(A)=102), (n(B)=95), (n\(A\cup B\)=143), and (n(U)=190), what is (n\(A^c\cap B^c\))?
Explanation opens after your attempt
Step 1
Concept
(A^c\cap B^c=\(A\cup B\)^c), so (190-143=47). Use De Morgan's law to identify the outside region.
Step 2
Why this answer is correct
The correct answer is A. (47). (A^c\cap B^c=\(A\cup B\)^c), so (190-143=47). Use De Morgan's law to identify the outside region.
Step 3
Exam Tip
(A^c\cap B^c=\(A\cup B\)^c), इसलिए (190-143=47)। डी मॉर्गन नियम से बाहर का क्षेत्र पहचानें।
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यदि (n(A)=90), (n(B)=85), (n\(A\cup B\)=125) और (n(U)=160) है, तो (n\(A^c\cap B^c\)) कितना होगा?
If (n(A)=90), (n(B)=85), (n\(A\cup B\)=125), and (n(U)=160), what is (n\(A^c\cap B^c\))?
Explanation opens after your attempt
Step 1
Concept
(A^c\cap B^c=\(A\cup B\)^c), so (160-125=35). Use De Morgan's law to identify the outside region.
Step 2
Why this answer is correct
The correct answer is A. (35). (A^c\cap B^c=\(A\cup B\)^c), so (160-125=35). Use De Morgan's law to identify the outside region.
Step 3
Exam Tip
(A^c\cap B^c=\(A\cup B\)^c), इसलिए (160-125=35)। डी मॉर्गन नियम से बाहर का क्षेत्र पहचानें।
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