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construct-equation MCQ Questions for Class 10

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3 questions tagged with construct-equation.

Question 1/3 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

यदि (4) और (9) किसी द्विघात समीकरण के मूल हैं, तो वह समीकरण कौनसा हो सकता है?

If (4) and (9) are roots of a quadratic equation, which equation can it be?

Explanation opens after your attempt
Correct Answer

A. \(x^2-13x+36=0\)

Step 1

Concept

If roots are (4) and (9), then ((x-4)(x-9)=0), that is \(x^2-13x+36=0\). In exams, form factors with opposite signs of roots.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-13x+36=0\). If roots are (4) and (9), then ((x-4)(x-9)=0), that is \(x^2-13x+36=0\). In exams, form factors with opposite signs of roots.

Step 3

Exam Tip

मूल (4) और (9) हों तो ((x-4)(x-9)=0), यानी \(x^2-13x+36=0\) है। परीक्षा में मूलों के विपरीत चिन्ह से गुणनखंड बनाएं।

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Question 2/3 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

यदि (3) और (7) किसी द्विघात समीकरण के मूल हैं, तो वह समीकरण कौनसा हो सकता है?

If (3) and (7) are roots of a quadratic equation, which equation can it be?

Explanation opens after your attempt
Correct Answer

A. \(x^2-10x+21=0\)

Step 1

Concept

If roots are (3) and (7), then ((x-3)(x-7)=0), that is \(x^2-10x+21=0\). In exams, form factors with opposite signs of roots.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-10x+21=0\). If roots are (3) and (7), then ((x-3)(x-7)=0), that is \(x^2-10x+21=0\). In exams, form factors with opposite signs of roots.

Step 3

Exam Tip

मूल (3) और (7) हों तो ((x-3)(x-7)=0), यानी \(x^2-10x+21=0\) है। परीक्षा में मूलों के विपरीत चिन्ह से गुणनखंड बनाएं।

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Question 3/3 Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

यदि (2) और (5) किसी द्विघात समीकरण के मूल हैं, तो वह समीकरण कौनसा हो सकता है?

If (2) and (5) are roots of a quadratic equation, which equation can it be?

Explanation opens after your attempt
Correct Answer

A. \(x^2-7x+10=0\)

Step 1

Concept

If the roots are (2) and (5), the equation is ((x-2)(x-5)=0), that is \(x^2-7x+10=0\). In exams, form factors with opposite signs of roots.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-7x+10=0\). If the roots are (2) and (5), the equation is ((x-2)(x-5)=0), that is \(x^2-7x+10=0\). In exams, form factors with opposite signs of roots.

Step 3

Exam Tip

मूल (2) और (5) हों तो समीकरण ((x-2)(x-5)=0) यानी \(x^2-7x+10=0\) है। परीक्षा में मूलों के विपरीत चिन्ह से गुणनखंड बनाएं।

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