यदि (f(x)=\frac{1}{x}) और (g(x)=x-1) हैं तो (\(f\circ g\)(x)+\(g\circ f\)(x)) का प्रांत क्या है?
If (f(x)=\frac{1}{x}) and (g(x)=x-1) then what is the domain of (\(f\circ g\)(x)+\(g\circ f\)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{0,1})
Concept
(\(f\circ g\)(x)=\frac{1}{x-1}) needs \(x\ne 1\) and (\(g\circ f\)(x)=\frac{1}{x}-1) needs \(x\ne 0\). In the sum both restrictions combine.
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{0,1}). (\(f\circ g\)(x)=\frac{1}{x-1}) needs \(x\ne 1\) and (\(g\circ f\)(x)=\frac{1}{x}-1) needs \(x\ne 0\). In the sum both restrictions combine.
Exam Tip
(\(f\circ g\)(x)=\frac{1}{x-1}) के लिए \(x\ne 1\) और (\(g\circ f\)(x)=\frac{1}{x}-1) के लिए \(x\ne 0\)। योग में दोनों प्रतिबंध मिलते हैं।
Login to save your score, XP, coins and progress.