class11 se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
1558 questions tagged with class11.
In how many ways can a set of (3) books be made from (9) books?
C. (84)
सेट बनाने में क्रम का महत्व नहीं होता। इसलिए \(\binom{9}{3}=84\) सही है। / Order is not important while making a set. Hence \(\binom{9}{3}=84\) is correct.
Login to save your score, XP, coins and progress.
In how many ways can a team of (6) students be selected from (8) students?
B. (28)
\(\binom{8}{6}=\binom{8}{2}=28\) होता है। अधिक चुनना हो तो न चुने गए लोगों को गिनना आसान होता है। / \(\binom{8}{6}=\binom{8}{2}=28\). When many are selected, counting those not selected is easier.
Login to save your score, XP, coins and progress.
How many ways are there to select a pair of (2) students from (15) students?
A. (105)
जोड़ी चुनने के तरीके \(\binom{15}{2}=105\) हैं। जोड़ी में क्रम नहीं गिना जाता। / The number of ways is \(\binom{15}{2}=105\). Order is not counted in a pair.
Login to save your score, XP, coins and progress.
In how many ways can at least (1) pencil be selected from (7) colored pencils?
C. (127)
कुल उपसमुच्चय \(2^7\) हैं और खाली चयन हटेगा। इसलिए \(2^7-1=127\) तरीके हैं। / Total subsets are \(2^7\), and the empty selection is removed. Hence the ways are \(2^7-1=127\).
Login to save your score, XP, coins and progress.
How many ways are there to choose (4) toys from (12) toys?
C. (495)
यह \(\binom{12}{4}=495\) है। बड़े मानों में सूत्र को क्रम से सरल करें। / This is \(\binom{12}{4}=495\). For larger values, simplify the formula step by step.
Login to save your score, XP, coins and progress.
From (5) boys and (5) girls, in how many ways can (1) boy and (1) girl be selected?
C. (25)
तरीके \(\binom{5}{1}\binom{5}{1}=25\) हैं। दोनों चयन स्वतंत्र हैं इसलिए गुणा करें। / The ways are \(\binom{5}{1}\binom{5}{1}=25\). The two selections are independent, so multiply.
Login to save your score, XP, coins and progress.
In how many ways can (3) letters be selected from (8) letters if order is not important?
B. (56)
क्रम महत्वपूर्ण नहीं है इसलिए \(\binom{8}{3}=56\) है। चयन वाले प्रश्नों में संयोजन लगाएं। / Order is not important, so \(\binom{8}{3}=56\). Use combinations in selection questions.
Login to save your score, XP, coins and progress.
How many line segments can be formed from (10) points?
B. (45)
एक रेखाखंड के लिए (2) बिंदु चाहिए। इसलिए \(\binom{10}{2}=45\) है। / A line segment needs (2) points. Therefore \(\binom{10}{2}=45\).
Login to save your score, XP, coins and progress.
How many ways are there to choose (2) digits from (6) digits if order is not considered?
B. (15)
क्रम नहीं देखना है इसलिए \(\binom{6}{2}=15\) है। यही संयोजन और क्रमचय का मुख्य अंतर है। / Order is not considered, so \(\binom{6}{2}=15\). This is the main difference between combination and permutation.
Login to save your score, XP, coins and progress.
How many ways are there to choose (3) pictures from (8) different pictures for an exhibition?
B. (56)
चयन \(\binom{8}{3}=56\) होगा। प्रदर्शनी के लिए चुनना संयोजन है। / The selection is \(\binom{8}{3}=56\). Choosing for an exhibition is a combination.
Login to save your score, XP, coins and progress.
How many ways are there to choose (4) songs from (9) songs?
C. (126)
गीत चुनना व्यवस्था नहीं है इसलिए \(\binom{9}{4}=126\) है। क्रम चाहिए होता तो अलग प्रश्न होता। / Choosing songs is not arrangement, so \(\binom{9}{4}=126\). If order were needed, it would be a different question.
Login to save your score, XP, coins and progress.
In how many ways can an invigilation team of (2) teachers be selected from (7) teachers?
B. (21)
टीम के लिए \(\binom{7}{2}=21\) चयन होंगे। टीम में क्रम नहीं होता। / For the team, there are \(\binom{7}{2}=21\) selections. A team has no order.
Login to save your score, XP, coins and progress.
A plate is to be made by choosing (2) dishes from (5) dishes. How many plates can be made?
A. (10)
दो व्यंजन चुनने के तरीके \(\binom{5}{2}=10\) हैं। थाली में क्रम का महत्व नहीं है। / The ways to choose two dishes are \(\binom{5}{2}=10\). The order on the plate is not important.
Login to save your score, XP, coins and progress.
In how many ways can a set of (3) questions be made from (10) different questions?
C. (120)
प्रश्नों का सेट बनाना चयन है। इसलिए \(\binom{10}{3}=120\) सही है। / Making a set of questions is selection. Hence \(\binom{10}{3}=120\) is correct.
Login to save your score, XP, coins and progress.
How many ways are there to select (5) students from (6) students for a competition?
B. (6)
\(\binom{6}{5}=\binom{6}{1}=6\) है। कभी-कभी न चुने गए व्यक्ति को गिनना आसान होता है। / \(\binom{6}{5}=\binom{6}{1}=6\). Sometimes counting the person not selected is easier.
Login to save your score, XP, coins and progress.
B. (28)
यह \(\binom{8}{2}=28\) है। कार्य समान हो तो चयन में क्रम नहीं गिना जाता। / This is \(\binom{8}{2}=28\). If the work is same, order is not counted in selection.
Login to save your score, XP, coins and progress.
From (4) white and (5) black balls, in how many ways can (2) black balls be selected?
A. (10)
केवल काली गेंदों में से चयन है इसलिए \(\binom{5}{2}=10\) होगा। बाकी सूचना केवल संदर्भ है। / Only black balls are selected, so \(\binom{5}{2}=10\). The remaining information is only context.
Login to save your score, XP, coins and progress.
From (5) pens and (6) pencils, in how many ways can (2) pens and (1) pencil be selected?
C. (60)
तरीके \(\binom{5}{2}\binom{6}{1}=10\cdot6=60\) हैं। प्रत्येक समूह से चयन अलग-अलग करें। / The ways are \(\binom{5}{2}\binom{6}{1}=10\cdot6=60\). Select from each group separately.
Login to save your score, XP, coins and progress.
B. (12)
चयन \(\binom{3}{1}\binom{4}{1}=12\) है। अलग प्रकारों में चयन की संख्याएं गुणा होती हैं। / The selection is \(\binom{3}{1}\binom{4}{1}=12\). Choices from different types are multiplied.
Login to save your score, XP, coins and progress.
What is the value of \(\binom{5}{2}+\binom{5}{3}\)?
C. (20)
\(\binom{5}{2}=10\) और \(\binom{5}{3}=10\) हैं। इसलिए कुल (20) है। / \(\binom{5}{2}=10\) and \(\binom{5}{3}=10\). Therefore the total is (20).
Login to save your score, XP, coins and progress.
What is the relation between \(\binom{6}{2}\) and \(\binom{6}{4}\)?
A. दोनों बराबर हैंThey are equal
क्योंकि \(\binom{n}{r}=\binom{n}{n-r}\) होता है। यहां (r=2) और (n-r=4) हैं। / Because \(\binom{n}{r}=\binom{n}{n-r}\). Here (r=2) and (n-r=4).
Login to save your score, XP, coins and progress.
If \(\binom{n}{0}=1\), for which (n) is it true?
C. हर \(n\geq0\)Every \(n\geq0\)
शून्य वस्तु चुनने का एक तरीका हर \(n\geq0\) के लिए होता है। यह मूल नियम है। / There is one way to choose zero objects for every \(n\geq0\). This is a basic rule.
Login to save your score, XP, coins and progress.
If \(\binom{n}{1}=14\), what is the value of (n)?
C. (14)
\(\binom{n}{1}=n\) होता है। इसलिए (n=14) मिलेगा। / \(\binom{n}{1}=n\). Therefore (n=14).
Login to save your score, XP, coins and progress.
What is the value of \(\binom{11}{1}+\binom{11}{0}\)?
C. (12)
मान \(\binom{11}{1}=11\) और \(\binom{11}{0}=1\) हैं। कुल (12) होगा। / The values are \(\binom{11}{1}=11\) and \(\binom{11}{0}=1\). The total is (12).
Login to save your score, XP, coins and progress.
Find the value of \(\binom{9}{2}\).
B. (36)
\(\binom{9}{2}=\frac{9\cdot8}{2}=36\) है। दो वस्तुओं के चयन में (2!) से भाग देना न भूलें। / \(\binom{9}{2}=\frac{9\cdot8}{2}=36\). Do not forget to divide by (2!) when choosing two objects.
Login to save your score, XP, coins and progress.
What is the value of \(\binom{12}{1}\)?
C. (12)
\(\binom{n}{1}=n\) होता है। इसलिए \(\binom{12}{1}=12\) सही है। / \(\binom{n}{1}=n\). Hence \(\binom{12}{1}=12\) is correct.
Login to save your score, XP, coins and progress.
What is the value of \(\binom{7}{7}\)?
B. (1)
सभी (7) वस्तुओं को चुनने का केवल एक तरीका है। अतः \(\binom{7}{7}=1\) है। / There is only one way to choose all (7) objects. Therefore \(\binom{7}{7}=1\).
Login to save your score, XP, coins and progress.
What will be the value of \(\binom{9}{0}\)?
B. (1)
किसी भी (n) के लिए \(\binom{n}{0}=1\) होता है। यह संयोजन की मूल पहचान है। / For any (n), \(\binom{n}{0}=1\). This is a basic identity of combinations.
Login to save your score, XP, coins and progress.
Find the value of \(\binom{10}{3}\).
C. (120)
\(\binom{10}{3}=\frac{10\cdot9\cdot8}{3\cdot2\cdot1}=120\) है। छोटे (r) के लिए सीधे गुणा करें। / \(\binom{10}{3}=\frac{10\cdot9\cdot8}{3\cdot2\cdot1}=120\). For small (r), multiply directly.
Login to save your score, XP, coins and progress.
What is the value of \(\binom{8}{2}\)?
C. (28)
\(\binom{8}{2}=\frac{8\cdot7}{2}=28\) है। दो वस्तुओं के चयन का सूत्र तेज होता है। / \(\binom{8}{2}=\frac{8\cdot7}{2}=28\). The formula for choosing two objects is quick.
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.