यदि (f(x)=x-2-1) और (g(x)=x-1) हैं, तो \(\frac{f}{g}\) का नियम और डोमेन क्या होगा?
If (f(x)=x-2-1) and (g(x)=x-1), what are the rule and domain of \(\frac{f}{g}\)?
Explanation opens after your attempt
Correct Answer
A. \(x+1,\ \mathbb{R}-{1}\)
Concept
\(\frac{x^2-1}{x-1}=x+1\), but (x=1) makes the original denominator zero. After cancellation, remember the removed point.
Why this answer is correct
The correct answer is A. \(x+1,\ \mathbb{R}-{1}\). \(\frac{x^2-1}{x-1}=x+1\), but (x=1) makes the original denominator zero. After cancellation, remember the removed point.
Exam Tip
\(\frac{x^2-1}{x-1}=x+1\), पर (x=1) मूल हर को शून्य करता है। रद्द करने के बाद भी हटाए गए बिंदु याद रखें।
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