यदि समान्तर श्रेणी में \(a_5+a_{17}=132\) है तो \(a_{11}\) का मान क्या होगा?
If in an AP \(a_5+a_{17}=132\), what is the value of \(a_{11}\)?
Explanation opens after your attempt
C. (66)
Concept
\(a_{11}\) is the middle term between \(a_5\) and \(a_{17}\). So \(a_{11}=\frac{132}{2}=66\).
Why this answer is correct
The correct answer is C. (66). \(a_{11}\) is the middle term between \(a_5\) and \(a_{17}\). So \(a_{11}=\frac{132}{2}=66\).
Exam Tip
\(a_5\) और \(a_{17}\) के बीच का पद \(a_{11}\) है। इसलिए \(a_{11}=\frac{132}{2}=66\)।
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