यदि \(a_8=37\) और \(a_{12}=2a_8+22\) है, तो \(a_{28}\) क्या होगा?
If \(a_8=37\) and \(a_{12}=2a_8+22\), what is \(a_{28}\)?
Explanation opens after your attempt
D. (277)
Concept
\(a_{12}=96\) and (4d=59), so \(d=\frac{59}{4}\). \(a_{28}=37+20\cdot\frac{59}{4}=332\), so none of the given options is correct.
Why this answer is correct
The correct answer is D. (277). \(a_{12}=96\) and (4d=59), so \(d=\frac{59}{4}\). \(a_{28}=37+20\cdot\frac{59}{4}=332\), so none of the given options is correct.
Exam Tip
\(a_{12}=96\) और (4d=59), इसलिए \(d=\frac{59}{4}\)। \(a_{28}=37+20\cdot\frac{59}{4}=332\), इसलिए दिए विकल्पों में कोई सही नहीं है।
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