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9 results found for "number-pair" in Class 10.

Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2-20x+96=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-20x+96=0\)?

Explanation opens after your attempt
Correct Answer

A. (-8) और (-12)(-8) and (-12)

Step 1

Concept

(-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 2

Why this answer is correct

The correct answer is A. (-8) और (-12) / (-8) and (-12). (-8+(-12)=-20) and ((-8)(-12)=96), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 3

Exam Tip

(-8+(-12)=-20) और ((-8)(-12)=96), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2-18x+80=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-18x+80=0\)?

Explanation opens after your attempt
Correct Answer

A. (-8) और (-10)(-8) and (-10)

Step 1

Concept

(-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 2

Why this answer is correct

The correct answer is A. (-8) और (-10) / (-8) and (-10). (-8+(-10)=-18) and ((-8)(-10)=80), so this pair is correct. In exams, when (c) is positive and (b) is negative, both numbers are negative.

Step 3

Exam Tip

(-8+(-10)=-18) और ((-8)(-10)=80), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक होती हैं।

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Question Medium Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2-14x+45=0\) में कौनसी संख्या जोड़ी मध्य पद बनाने में मदद करेगी?

Which number pair helps in making the middle term in \(x^2-14x+45=0\)?

Explanation opens after your attempt
Correct Answer

A. (-5) और (-9)(-5) and (-9)

Step 1

Concept

(-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.

Step 2

Why this answer is correct

The correct answer is A. (-5) और (-9) / (-5) and (-9). (-5+(-9)=-14) and ((-5)(-9)=45), so this pair is correct. In exams, if (c) is positive and (b) is negative, both numbers may be negative.

Step 3

Exam Tip

(-5+(-9)=-14) और ((-5)(-9)=45), इसलिए यह जोड़ी सही है। परीक्षा में (c) धनात्मक और (b) ऋणात्मक हो तो दोनों संख्याएं ऋणात्मक हो सकती हैं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 36

\(x^2+3x-40=0\) में मध्य पद बनाने के लिए कौनसी संख्या जोड़ी सही है?

Which number pair is correct for making the middle term in \(x^2+3x-40=0\)?

Explanation opens after your attempt
Correct Answer

A. (8) और (-5)(8) and (-5)

Step 1

Concept

(8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 2

Why this answer is correct

The correct answer is A. (8) और (-5) / (8) and (-5). (8+(-5)=3) and \(8\times(-5)=-40\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 3

Exam Tip

(8+(-5)=3) और \(8\times(-5)=-40\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 35

\(x^2+2x-24=0\) में मध्य पद बनाने के लिए कौनसी संख्या जोड़ी सही है?

Which number pair is correct for making the middle term in \(x^2+2x-24=0\)?

Explanation opens after your attempt
Correct Answer

A. (6) और (-4)(6) and (-4)

Step 1

Concept

(6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 2

Why this answer is correct

The correct answer is A. (6) और (-4) / (6) and (-4). (6+(-4)=2) and \(6\times(-4)=-24\), so this pair is correct. In exams, match the sum with (b) and product with (c).

Step 3

Exam Tip

(6+(-4)=2) और \(6\times(-4)=-24\), इसलिए यह जोड़ी सही है। परीक्षा में योग (b) और गुणनफल (c) से मिलाएं।

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Question Easy Mathematics Quadratic Equations Methods of Solving Quadratic Equations Class 10 Level 34

\(x^2+2x-15=0\) में कौनसी संख्या जोड़ी गुणनखंड बनाने में मदद करेगी?

Which number pair helps in factoring \(x^2+2x-15=0\)?

Explanation opens after your attempt
Correct Answer

A. (5) और (-3)(5) and (-3)

Step 1

Concept

(5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.

Step 2

Why this answer is correct

The correct answer is A. (5) और (-3) / (5) and (-3). (5+(-3)=2) and \(5\times(-3)=-15\), so this pair is correct. In exams, split the middle term using such a pair.

Step 3

Exam Tip

(5+(-3)=2) और \(5\times(-3)=-15\), इसलिए यह जोड़ी सही है। परीक्षा में मध्य पद को इसी जोड़ी से तोड़ें।

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Question Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(x^2-17x+72=0\) के गुणनखंड पहचानने के लिए कौन-सी संख्या जोड़ी उपयोगी है?

Which pair of numbers is useful to identify the factors of \(x^2-17x+72=0\)?

Explanation opens after your attempt
Correct Answer

A. (8) और (9)(8) and (9)

Step 1

Concept

\(8\cdot9=72\) and (8+9=17). Because the middle term is negative, the factors are ((x-8)(x-9)).

Step 2

Why this answer is correct

The correct answer is A. (8) और (9) / (8) and (9). \(8\cdot9=72\) and (8+9=17). Because the middle term is negative, the factors are ((x-8)(x-9)).

Step 3

Exam Tip

\(8\cdot9=72\) और (8+9=17) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-8)(x-9)) बनते हैं।

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Question Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(x^2-13x+42=0\) के गुणनखंड पहचानने के लिए कौन-सी संख्या जोड़ी उपयोगी है?

Which pair of numbers is useful to identify the factors of \(x^2-13x+42=0\)?

Explanation opens after your attempt
Correct Answer

A. (6) और (7)(6) and (7)

Step 1

Concept

\(6\cdot7=42\) and (6+7=13). Because the middle term is negative, the factors are ((x-6)(x-7)).

Step 2

Why this answer is correct

The correct answer is A. (6) और (7) / (6) and (7). \(6\cdot7=42\) and (6+7=13). Because the middle term is negative, the factors are ((x-6)(x-7)).

Step 3

Exam Tip

\(6\cdot7=42\) और (6+7=13) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-6)(x-7)) बनते हैं।

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Question Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(x^2-11x+30=0\) में मूलों की पहचान के लिए कौन-सी संख्या जोड़ी उपयोगी है?

Which pair of numbers is useful to identify the roots of \(x^2-11x+30=0\)?

Explanation opens after your attempt
Correct Answer

A. (5) और (6)(5) and (6)

Step 1

Concept

\(5\cdot6=30\) and (5+6=11). Because the middle term is negative, the factors are ((x-5)(x-6)).

Step 2

Why this answer is correct

The correct answer is A. (5) और (6) / (5) and (6). \(5\cdot6=30\) and (5+6=11). Because the middle term is negative, the factors are ((x-5)(x-6)).

Step 3

Exam Tip

\(5\cdot6=30\) और (5+6=11) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-5)(x-6)) बनते हैं।

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