(x-2-(a+6)x+6a=0) के लिए कौन-सा कथन हमेशा सत्य है?
Which statement is always true for (x-2-(a+6)x+6a=0)?
Explanation opens after your attempt
B. (6) हमेशा जड़ है(6) is always a root
Concept
Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Why this answer is correct
The correct answer is B. (6) हमेशा जड़ है / (6) is always a root. Putting (x=6) gives (36-6(a+6)+6a=0). Hence (6) is always one root and the other root is (a).
Exam Tip
(x=6) रखने पर (36-6(a+6)+6a=0) मिलता है। इसलिए (6) हमेशा एक जड़ है और दूसरी जड़ (a) है।
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