Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(\frac{\sqrt{3}}{\sqrt{12}}\) का मान है?

Which option is the value of \(\frac{\sqrt{3}}{\sqrt{12}}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\)

Step 1

Concept

\(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\). Simplify the ratio inside the roots.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\). \(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\). Simplify the ratio inside the roots.

Step 3

Exam Tip

\(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\) है। जड़ों के भाग में अनुपात सरल करें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\frac{\sqrt{3}}{\sqrt{12}}\) का मान है? / Which option is the value of \(\frac{\sqrt{3}}{\sqrt{12}}\)?

Correct Answer: A. \(\frac{1}{2}\). Explanation: \(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\) है। जड़ों के भाग में अनुपात सरल करें। / \(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\). Simplify the ratio inside the roots.

Which concept should I revise for this Mathematics MCQ?

\(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\). Simplify the ratio inside the roots.

What exam hint can help solve this Mathematics question?

\(\frac{\sqrt{3}}{\sqrt{12}}=\sqrt{\frac{3}{12}}=\sqrt{\frac{1}{4}}=\frac{1}{2}\) है। जड़ों के भाग में अनुपात सरल करें।

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