Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(\frac{\sqrt{27}+\sqrt{12}}{\sqrt{3}}\) का मान है?

Which option is the value of \(\frac{\sqrt{27}+\sqrt{12}}{\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so the numerator is \(5\sqrt{3}\). Dividing gives (5).

Step 2

Why this answer is correct

The correct answer is A. (5). \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so the numerator is \(5\sqrt{3}\). Dividing gives (5).

Step 3

Exam Tip

\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\), इसलिए अंश \(5\sqrt{3}\) है। भाग देने पर (5) मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\frac{\sqrt{27}+\sqrt{12}}{\sqrt{3}}\) का मान है? / Which option is the value of \(\frac{\sqrt{27}+\sqrt{12}}{\sqrt{3}}\)?

Correct Answer: A. (5). Explanation: \(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\), इसलिए अंश \(5\sqrt{3}\) है। भाग देने पर (5) मिलता है। / \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so the numerator is \(5\sqrt{3}\). Dividing gives (5).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so the numerator is \(5\sqrt{3}\). Dividing gives (5).

What exam hint can help solve this Mathematics question?

\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\), इसलिए अंश \(5\sqrt{3}\) है। भाग देने पर (5) मिलता है।

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