Hard Mathematics Polynomials Class 10 Level 25

कौन सा विकल्प \(4\sqrt{3}+3\sqrt{12}-2\sqrt{75}\) का मान है?

Which option is the value of \(4\sqrt{3}+3\sqrt{12}-2\sqrt{75}\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\). So \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\).

Step 2

Why this answer is correct

The correct answer is A. (0). \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\). So \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\).

Step 3

Exam Tip

\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{75}=5\sqrt{3}\) है। इसलिए \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(4\sqrt{3}+3\sqrt{12}-2\sqrt{75}\) का मान है? / Which option is the value of \(4\sqrt{3}+3\sqrt{12}-2\sqrt{75}\)?

Correct Answer: A. (0). Explanation: \(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{75}=5\sqrt{3}\) है। इसलिए \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\) है। / \(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\). So \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{12}=2\sqrt{3}\) and \(\sqrt{75}=5\sqrt{3}\). So \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\).

What exam hint can help solve this Mathematics question?

\(\sqrt{12}=2\sqrt{3}\) और \(\sqrt{75}=5\sqrt{3}\) है। इसलिए \(4\sqrt{3}+6\sqrt{3}-10\sqrt{3}=0\) है।

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