Medium Mathematics Polynomials Class 10 Level 27

कौन सा विकल्प \(\sqrt{7}+\sqrt{63}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{7}+\sqrt{63}\)?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{7}\)

Step 1

Concept

\(\sqrt{63}=3\sqrt{7}\), so the sum is \(4\sqrt{7}\). Simplify roots first and then add like terms.

Step 2

Why this answer is correct

The correct answer is A. \(4\sqrt{7}\). \(\sqrt{63}=3\sqrt{7}\), so the sum is \(4\sqrt{7}\). Simplify roots first and then add like terms.

Step 3

Exam Tip

\(\sqrt{63}=3\sqrt{7}\) है इसलिए योग \(4\sqrt{7}\) है। पहले जड़ सरल करें फिर समान पद जोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\sqrt{7}+\sqrt{63}\) का सरल रूप है? / Which option is the simplified form of \(\sqrt{7}+\sqrt{63}\)?

Correct Answer: A. \(4\sqrt{7}\). Explanation: \(\sqrt{63}=3\sqrt{7}\) है इसलिए योग \(4\sqrt{7}\) है। पहले जड़ सरल करें फिर समान पद जोड़ें। / \(\sqrt{63}=3\sqrt{7}\), so the sum is \(4\sqrt{7}\). Simplify roots first and then add like terms.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{63}=3\sqrt{7}\), so the sum is \(4\sqrt{7}\). Simplify roots first and then add like terms.

What exam hint can help solve this Mathematics question?

\(\sqrt{63}=3\sqrt{7}\) है इसलिए योग \(4\sqrt{7}\) है। पहले जड़ सरल करें फिर समान पद जोड़ें।

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