कौन सा विकल्प \(\sqrt{12}+\sqrt{27}+\sqrt{75}-\sqrt{48}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{12}+\sqrt{27}+\sqrt{75}-\sqrt{48}\)?
Explanation opens after your attempt
A. \(6\sqrt{3}\)
Concept
It is \(2\sqrt{3}+3\sqrt{3}+5\sqrt{3}-4\sqrt{3}=6\sqrt{3}\). Add like radical terms.
Why this answer is correct
The correct answer is A. \(6\sqrt{3}\). It is \(2\sqrt{3}+3\sqrt{3}+5\sqrt{3}-4\sqrt{3}=6\sqrt{3}\). Add like radical terms.
Exam Tip
यह \(2\sqrt{3}+3\sqrt{3}+5\sqrt{3}-4\sqrt{3}=6\sqrt{3}\) है। समान जड़ वाले पद जोड़ें।
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