Medium Mathematics Quadratic Equations Class 10 Level 29

कौन-सा विकल्प सामान्य रूप में द्विघात समीकरण नहीं है?

Which option is not a quadratic equation in the usual form?

Explanation opens after your attempt
Correct Answer

C. \(\sqrt{x}+x=4\)

Step 1

Concept

The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{x}+x=4\). The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

Step 3

Exam Tip

\(\sqrt{x}\) में चर की भिन्न घात है, इसलिए यह सामान्य द्विघात रूप नहीं है। द्विघात रूप में केवल \(x^2\), (x) और स्थिर पद होते हैं।

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Mathematics Answer, Explanation and Revision Hints

कौन-सा विकल्प सामान्य रूप में द्विघात समीकरण नहीं है? / Which option is not a quadratic equation in the usual form?

Correct Answer: C. \(\sqrt{x}+x=4\). Explanation: \(\sqrt{x}\) में चर की भिन्न घात है, इसलिए यह सामान्य द्विघात रूप नहीं है। द्विघात रूप में केवल \(x^2\), (x) और स्थिर पद होते हैं। / The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

Which concept should I revise for this Mathematics MCQ?

The term \(\sqrt{x}\) has a fractional power of the variable, so it is not in usual quadratic form. Quadratic form has only \(x^2\), (x), and constant terms.

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) में चर की भिन्न घात है, इसलिए यह सामान्य द्विघात रूप नहीं है। द्विघात रूप में केवल \(x^2\), (x) और स्थिर पद होते हैं।

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