Expert Mathematics Polynomials Class 10 Level 27

कौन सा विकल्प \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) के गलत होने का सही प्रतिउदाहरण है?

Which option is a correct counterexample showing that \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) is false?

Explanation opens after your attempt
Correct Answer

A. (a=9) और (b=16)(a=9) and (b=16)

Step 1

Concept

\(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.

Step 2

Why this answer is correct

The correct answer is A. (a=9) और (b=16) / (a=9) and (b=16). \(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.

Step 3

Exam Tip

\(\sqrt{9+16}=5\) है जबकि \(\sqrt{9}+\sqrt{16}=7\) है। परीक्षा में मूल के अंदर के योग को अलग-अलग न तोड़ें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein.

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) के गलत होने का सही प्रतिउदाहरण है? / Which option is a correct counterexample showing that \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) is false?

Correct Answer: A. (a=9) और (b=16) / (a=9) and (b=16). Explanation: \(\sqrt{9+16}=5\) है जबकि \(\sqrt{9}+\sqrt{16}=7\) है। परीक्षा में मूल के अंदर के योग को अलग-अलग न तोड़ें। / \(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.

What exam hint can help solve this Mathematics question?

\(\sqrt{9+16}=5\) है जबकि \(\sqrt{9}+\sqrt{16}=7\) है। परीक्षा में मूल के अंदर के योग को अलग-अलग न तोड़ें।

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.