कौन सा विकल्प \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) के गलत होने का सही प्रतिउदाहरण है?
Which option is a correct counterexample showing that \(\sqrt{a+b}=\sqrt{a}+\sqrt{b}\) is false?
Explanation opens after your attempt
A. (a=9) और (b=16)(a=9) and (b=16)
Concept
\(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.
Why this answer is correct
The correct answer is A. (a=9) और (b=16) / (a=9) and (b=16). \(\sqrt{9+16}=5\) while \(\sqrt{9}+\sqrt{16}=7\). In exams do not split addition inside a radical.
Exam Tip
\(\sqrt{9+16}=5\) है जबकि \(\sqrt{9}+\sqrt{16}=7\) है। परीक्षा में मूल के अंदर के योग को अलग-अलग न तोड़ें।
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