Medium Mathematics Quadratic Equations Class 10 Level 30

किस विकल्प में (x=3) और (x=8) मूल हैं?

Which option has roots (x=3) and (x=8)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-11x+24=0\)

Step 1

Concept

If the roots are (3) and (8), the factors are ((x-3)) and ((x-8)). Their product gives \(x^2-11x+24=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-11x+24=0\). If the roots are (3) and (8), the factors are ((x-3)) and ((x-8)). Their product gives \(x^2-11x+24=0\).

Step 3

Exam Tip

मूल (3) और (8) हों तो गुणनखंड ((x-3)) और ((x-8)) होंगे। इनका गुणन \(x^2-11x+24=0\) देता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

किस विकल्प में (x=3) और (x=8) मूल हैं? / Which option has roots (x=3) and (x=8)?

Correct Answer: A. \(x^2-11x+24=0\). Explanation: मूल (3) और (8) हों तो गुणनखंड ((x-3)) और ((x-8)) होंगे। इनका गुणन \(x^2-11x+24=0\) देता है। / If the roots are (3) and (8), the factors are ((x-3)) and ((x-8)). Their product gives \(x^2-11x+24=0\).

Which concept should I revise for this Mathematics MCQ?

If the roots are (3) and (8), the factors are ((x-3)) and ((x-8)). Their product gives \(x^2-11x+24=0\).

What exam hint can help solve this Mathematics question?

मूल (3) और (8) हों तो गुणनखंड ((x-3)) और ((x-8)) होंगे। इनका गुणन \(x^2-11x+24=0\) देता है।

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