कौन सा फलन विषम है?

Which function is odd?

Explanation opens after your attempt
Correct Answer

A. \(\sin^{-1}x\)

Step 1

Concept

Since (\sin^{-1}(-x)=-\sin^{-1}x), \(\sin^{-1}x\) is odd. The function \(\tan^{-1}x\) is also odd but is not in the options.

Step 2

Why this answer is correct

The correct answer is A. \(\sin^{-1}x\). Since (\sin^{-1}(-x)=-\sin^{-1}x), \(\sin^{-1}x\) is odd. The function \(\tan^{-1}x\) is also odd but is not in the options.

Step 3

Exam Tip

(\sin^{-1}(-x)=-\sin^{-1}x) इसलिए \(\sin^{-1}x\) विषम है। \(\tan^{-1}x\) भी विषम होता है पर विकल्प में नहीं है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

कौन सा फलन विषम है? / Which function is odd?

Correct Answer: A. \(\sin^{-1}x\). Explanation: (\sin^{-1}(-x)=-\sin^{-1}x) इसलिए \(\sin^{-1}x\) विषम है। \(\tan^{-1}x\) भी विषम होता है पर विकल्प में नहीं है। / Since (\sin^{-1}(-x)=-\sin^{-1}x), \(\sin^{-1}x\) is odd. The function \(\tan^{-1}x\) is also odd but is not in the options.

Which concept should I revise for this Mathematics MCQ?

Since (\sin^{-1}(-x)=-\sin^{-1}x), \(\sin^{-1}x\) is odd. The function \(\tan^{-1}x\) is also odd but is not in the options.

What exam hint can help solve this Mathematics question?

(\sin^{-1}(-x)=-\sin^{-1}x) इसलिए \(\sin^{-1}x\) विषम है। \(\tan^{-1}x\) भी विषम होता है पर विकल्प में नहीं है।

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.