The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.
Step 2
Why this answer is correct
The correct answer is A. \(\sin^{-1}2\). The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.
Step 3
Exam Tip
\(\sin^{-1}x\) केवल \(x\in[-1,1]\) के लिए परिभाषित है और \(2\notin[-1,1]\)। डोमेन आधारित प्रश्नों में विकल्प तुरंत जांचें।
Mathematics Answer, Explanation and Revision Hints
कौन सा व्यंजक परिभाषित नहीं है? / Which expression is not defined?
Correct Answer: A. \(\sin^{-1}2\). Explanation: \(\sin^{-1}x\) केवल \(x\in[-1,1]\) के लिए परिभाषित है और \(2\notin[-1,1]\)। डोमेन आधारित प्रश्नों में विकल्प तुरंत जांचें। / The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.
Which concept should I revise for this Mathematics MCQ?
The expression \(\sin^{-1}x\) is defined only for \(x\in[-1,1]\), and \(2\notin[-1,1]\). In domain questions check each option quickly.
What exam hint can help solve this Mathematics question?
\(\sin^{-1}x\) केवल \(x\in[-1,1]\) के लिए परिभाषित है और \(2\notin[-1,1]\)। डोमेन आधारित प्रश्नों में विकल्प तुरंत जांचें।
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