कौन सा व्यंजक वास्तविक संख्या नहीं देता?

Which expression does not give a real number?

Explanation opens after your attempt
Correct Answer

A. (\cos^{-1}\left\(\frac{7}{6}\right\))

Step 1

Concept

The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

Step 2

Why this answer is correct

The correct answer is A. (\cos^{-1}\left\(\frac{7}{6}\right\)). The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

Step 3

Exam Tip

\(\cos^{-1}x\) केवल \(x\in[-1,1]\) पर वास्तविक है और \(\frac{7}{6}>1\) है। इसलिए यह वास्तविक मान नहीं देगा।

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Mathematics Answer, Explanation and Revision Hints

कौन सा व्यंजक वास्तविक संख्या नहीं देता? / Which expression does not give a real number?

Correct Answer: A. (\cos^{-1}\left\(\frac{7}{6}\right\)). Explanation: \(\cos^{-1}x\) केवल \(x\in[-1,1]\) पर वास्तविक है और \(\frac{7}{6}>1\) है। इसलिए यह वास्तविक मान नहीं देगा। / The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

Which concept should I revise for this Mathematics MCQ?

The expression \(\cos^{-1}x\) is real only for \(x\in[-1,1]\), and \(\frac{7}{6}>1\). Hence it will not give a real value.

What exam hint can help solve this Mathematics question?

\(\cos^{-1}x\) केवल \(x\in[-1,1]\) पर वास्तविक है और \(\frac{7}{6}>1\) है। इसलिए यह वास्तविक मान नहीं देगा।

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