Easy Mathematics Quadratic Equations Class 10 Level 37

किस समीकरण के वास्तविक मूल नहीं होंगे?

Which equation will have no real roots?

Explanation opens after your attempt
Correct Answer

A. \(x^2+3x+5=0\)

Step 1

Concept

For the first equation, (D=32-4(1)(5)=-11<0). A negative discriminant gives no real roots.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+3x+5=0\). For the first equation, (D=32-4(1)(5)=-11<0). A negative discriminant gives no real roots.

Step 3

Exam Tip

पहले समीकरण में (D=32-4(1)(5)=-11<0) है। ऋणात्मक विविक्तकर वास्तविक मूल नहीं देता।

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किस समीकरण के वास्तविक मूल नहीं होंगे? / Which equation will have no real roots?

Correct Answer: A. \(x^2+3x+5=0\). Explanation: पहले समीकरण में (D=32-4(1)(5)=-11<0) है। ऋणात्मक विविक्तकर वास्तविक मूल नहीं देता। / For the first equation, (D=32-4(1)(5)=-11<0). A negative discriminant gives no real roots.

Which concept should I revise for this Mathematics MCQ?

For the first equation, (D=32-4(1)(5)=-11<0). A negative discriminant gives no real roots.

What exam hint can help solve this Mathematics question?

पहले समीकरण में (D=32-4(1)(5)=-11<0) है। ऋणात्मक विविक्तकर वास्तविक मूल नहीं देता।

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