Easy Mathematics Quadratic Equations Class 10 Level 32

किस समीकरण के मूल (-2) और (6) हैं?

Which equation has roots (-2) and (6)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x-12=0\)

Step 1

Concept

With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x-12=0\). With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).

Step 3

Exam Tip

मूल (-2) और (6) होने पर ((x+2)(x-6)=0) होगा। इसे खोलने पर \(x^2-4x-12=0\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

किस समीकरण के मूल (-2) और (6) हैं? / Which equation has roots (-2) and (6)?

Correct Answer: A. \(x^2-4x-12=0\). Explanation: मूल (-2) और (6) होने पर ((x+2)(x-6)=0) होगा। इसे खोलने पर \(x^2-4x-12=0\) मिलता है। / With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).

Which concept should I revise for this Mathematics MCQ?

With roots (-2) and (6), we get ((x+2)(x-6)=0). Expanding it gives \(x^2-4x-12=0\).

What exam hint can help solve this Mathematics question?

मूल (-2) और (6) होने पर ((x+2)(x-6)=0) होगा। इसे खोलने पर \(x^2-4x-12=0\) मिलता है।

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