समीकरण \(12-7x+x^2=0\) को \(ax^2+bx+c=0\) के रूप में लिखने पर (b) का मान क्या होगा?
When \(12-7x+x^2=0\) is written as \(ax^2+bx+c=0\), what is the value of (b)?
Explanation opens after your attempt
B. (-7)
Concept
In proper order, the equation is \(x^2-7x+12=0\). So the coefficient of (x) is (b=-7).
Why this answer is correct
The correct answer is B. (-7). In proper order, the equation is \(x^2-7x+12=0\). So the coefficient of (x) is (b=-7).
Exam Tip
सही क्रम में समीकरण \(x^2-7x+12=0\) है। इसलिए (x) का गुणांक (b=-7) है।
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