समीकरण (2x+3y=6) और (kx+6y=15) का कोई हल न होने के लिए (k) क्या होगा?

What will (k) be for (2x+3y=6) and (kx+6y=15) to have no solution?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

For no solution (2/k=3/6) and (6/15) must be different. This gives (k=4).

Step 2

Why this answer is correct

The correct answer is C. (4). For no solution (2/k=3/6) and (6/15) must be different. This gives (k=4).

Step 3

Exam Tip

कोई हल नहीं के लिए (2/k=3/6) और (6/15) अलग होना चाहिए। इससे (k=4) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण (2x+3y=6) और (kx+6y=15) का कोई हल न होने के लिए (k) क्या होगा? / What will (k) be for (2x+3y=6) and (kx+6y=15) to have no solution?

Correct Answer: C. (4). Explanation: कोई हल नहीं के लिए (2/k=3/6) और (6/15) अलग होना चाहिए। इससे (k=4) मिलता है। / For no solution (2/k=3/6) and (6/15) must be different. This gives (k=4).

Which concept should I revise for this Mathematics MCQ?

For no solution (2/k=3/6) and (6/15) must be different. This gives (k=4).

What exam hint can help solve this Mathematics question?

कोई हल नहीं के लिए (2/k=3/6) और (6/15) अलग होना चाहिए। इससे (k=4) मिलता है।

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