Hard Mathematics Quadratic Equations Class 10 Level 35

\(5x^2-18x+9=0\) के मूल क्या होंगे?

What will be the roots of \(5x^2-18x+9=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=3,\frac{3}{5}\)

Step 1

Concept

(5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.

Step 2

Why this answer is correct

The correct answer is A. \(x=3,\frac{3}{5}\). (5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.

Step 3

Exam Tip

(5x-2-18x+9=(5x-3)(x-3)), इसलिए मूल \(\frac{3}{5}\) और (3) हैं। परीक्षा में गुणनखंड विधि से उत्तर जल्दी जांचें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(5x^2-18x+9=0\) के मूल क्या होंगे? / What will be the roots of \(5x^2-18x+9=0\)?

Correct Answer: A. \(x=3,\frac{3}{5}\). Explanation: (5x-2-18x+9=(5x-3)(x-3)), इसलिए मूल \(\frac{3}{5}\) और (3) हैं। परीक्षा में गुणनखंड विधि से उत्तर जल्दी जांचें। / (5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.

Which concept should I revise for this Mathematics MCQ?

(5x-2-18x+9=(5x-3)(x-3)), so the roots are \(\frac{3}{5}\) and (3). In exams, verify the answer quickly by factorisation.

What exam hint can help solve this Mathematics question?

(5x-2-18x+9=(5x-3)(x-3)), इसलिए मूल \(\frac{3}{5}\) और (3) हैं। परीक्षा में गुणनखंड विधि से उत्तर जल्दी जांचें।

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