समीकरण \(4x^2+4x+1=0\) में (a+b+c) का मान क्या है?
What is the value of (a+b+c) for \(4x^2+4x+1=0\)?
Explanation opens after your attempt
C. (9)
Concept
Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).
Why this answer is correct
The correct answer is C. (9). Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).
Exam Tip
यहां (a=4), (b=4), (c=1) हैं। इसलिए (a+b+c=9) है।
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