Easy Mathematics Quadratic Equations Class 10 Level 28

समीकरण \(4x^2+4x+1=0\) में (a+b+c) का मान क्या है?

What is the value of (a+b+c) for \(4x^2+4x+1=0\)?

Explanation opens after your attempt
Correct Answer

C. (9)

Step 1

Concept

Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).

Step 2

Why this answer is correct

The correct answer is C. (9). Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).

Step 3

Exam Tip

यहां (a=4), (b=4), (c=1) हैं। इसलिए (a+b+c=9) है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(4x^2+4x+1=0\) में (a+b+c) का मान क्या है? / What is the value of (a+b+c) for \(4x^2+4x+1=0\)?

Correct Answer: C. (9). Explanation: यहां (a=4), (b=4), (c=1) हैं। इसलिए (a+b+c=9) है। / Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).

Which concept should I revise for this Mathematics MCQ?

Here (a=4), (b=4), (c=1). Therefore (a+b+c=9).

What exam hint can help solve this Mathematics question?

यहां (a=4), (b=4), (c=1) हैं। इसलिए (a+b+c=9) है।

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