समीकरण \(5x^2+6x+1=0\) में मूलों के वर्गों का योग क्या है?
What is the sum of squares of the roots of \(5x^2+6x+1=0\)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{26}{25} \)
Concept
(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here (\left\(-\frac{6}{5}\right\)2-2\cdot\frac{1}{5}=\frac{26}{25}).
Why this answer is correct
The correct answer is A. \( \frac{26}{25} \). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here (\left\(-\frac{6}{5}\right\)2-2\cdot\frac{1}{5}=\frac{26}{25}).
Exam Tip
(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। यहाँ (\left\(-\frac{6}{5}\right\)2-2\cdot\frac{1}{5}=\frac{26}{25})।
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