Expert Mathematics Quadratic Equations Class 10 Level 29

समीकरण \(4x^2+8x+3=0\) में मूलों के वर्गों का योग क्या है?

What is the sum of squares of the roots of \(4x^2+8x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \( \frac{5}{2} \)

Step 1

Concept

(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2}).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{5}{2} \). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2}).

Step 3

Exam Tip

(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। यहाँ ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2})।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(4x^2+8x+3=0\) में मूलों के वर्गों का योग क्या है? / What is the sum of squares of the roots of \(4x^2+8x+3=0\)?

Correct Answer: A. \( \frac{5}{2} \). Explanation: (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। यहाँ ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2})। / (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2}).

Which concept should I revise for this Mathematics MCQ?

(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). Here ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2}).

What exam hint can help solve this Mathematics question?

(\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। यहाँ ((-2)2-2\cdot\frac{3}{4}=\frac{5}{2})।

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