Medium Mathematics Quadratic Equations Class 10 Level 29

समीकरण \(4x^2-7x+2=0\) में मूलों का योग क्या है?

What is the sum of roots of \(4x^2-7x+2=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{7}{4}\)

Step 1

Concept

The sum of roots is \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\). Pay attention to the sign of (b) in the formula.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7}{4}\). The sum of roots is \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\). Pay attention to the sign of (b) in the formula.

Step 3

Exam Tip

मूलों का योग \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\) है। सूत्र में (b) का चिन्ह ध्यान से रखें।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(4x^2-7x+2=0\) में मूलों का योग क्या है? / What is the sum of roots of \(4x^2-7x+2=0\)?

Correct Answer: A. \(\frac{7}{4}\). Explanation: मूलों का योग \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\) है। सूत्र में (b) का चिन्ह ध्यान से रखें। / The sum of roots is \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\). Pay attention to the sign of (b) in the formula.

Which concept should I revise for this Mathematics MCQ?

The sum of roots is \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\). Pay attention to the sign of (b) in the formula.

What exam hint can help solve this Mathematics question?

मूलों का योग \(-\frac{b}{a}=-\frac{-7}{4}=\frac{7}{4}\) है। सूत्र में (b) का चिन्ह ध्यान से रखें।

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