समीकरण ((x-6)2=4x+5) का मानक रूप कौन-सा है?
What is the standard form of ((x-6)2=4x+5)?
Explanation opens after your attempt
A. \(x^2-16x+31=0\)
Concept
((x-6)2=x-2-12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).
Why this answer is correct
The correct answer is A. \(x^2-16x+31=0\). ((x-6)2=x-2-12x+36). Subtracting (4x+5) gives \(x^2-16x+31=0\).
Exam Tip
((x-6)2=x-2-12x+36) है। (4x+5) को घटाने पर \(x^2-16x+31=0\) मिलता है।
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